**Similar Questions for How Many Cm3 To A Liter from ***Yahoo Answers***Question**How many liters of seawater would have to be processed to recover 1 kg of gold?A cubic meter of ocean water has 6 x 10^-6 g gold. If the total mass of the water in Earth's oceans is 4 x 10^20kg, how many kilograms of gold are distributed throughout the oceans? Assume that the density of seawater is 1g/cm3. How many liters of seawater would have to be processed to recover 1 kg of gold.
There's two questions to this problem. I would like to know how you would sove this problem and what's the answer?

**Answer**To get kg of gold, first, you convert your density in g/cc to Kg/m^3 which is 1000 kg/m^3. But since total mass of the water in Earth's oceans is 4 x 10^20kg, you can get the the volume of the water in the oceans.
4 x 10^20kg/1000 kg/m^3 = 4 x 10^17 m^3.
But one cubic meter of ocean water has 6 x 10^-6 g gold, so
4 x 10^17 m^3 x (6 x 10^-6 g gold/m^3) = 24 x 10^11 g of gold
or converting to kilograms = 24 x 10^8 Kg.
To get the number of liters, use 6 x 10^-6 g gold/ m^3 or convert to 6x10^-9 kg/m^3.
and use the following conversion factors,
1 liter = 1000 cc or cm^3
m = 100 cm, m^3 = 10^6 cm^3, you should get
1.667 x 10^11(!!! ) Liters just to recover 1 kg of gold!!!
So you see, nobody is applying to mine the oceans for gold.

**Question****Answer**1 cm^3 = 1 mL. 1000 mL = 1 L.
Standard conversion you should have memorized at the beginning of your chem class. :)

**Question****Answer**1 H atom weight is 1/(6.02*10+23) or about 1.7x10-24 gram. Then 1.7*10-24 g/1.5*10-29 g/cm3 = 1.2 x 10+5 cm3 or abut 120 L.